The net charge within the cylinder is (-44.25 pC)

Explanation:

Given that,

Total electric flux,

Length of the cylinder, l = 1.2 m

Diameter of the cylinder, d = 0.2 m

We know that the Gauss's law of electrostatics gives the relation between electric flux and the net charge. It is given by :

q is net charge within the cylinder

So, the net charge within the cylinder is (-44.25 pC). Hence, this is the required solution.

it is the second option.

the grams of oxygen gas that can be produced is 20.6 grams of o₂

calculation

2liclo₃ → 2 licl + 3 o₂

step 1: find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5 +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281 moles

step 2: use the mole ratio to calculate the moles of o2

from equation above, liclo₃: o₂ is 2: 3

therefore the moles of o₂=0.4281 moles x3/2 =0.6422 moles

step 3: find mass of o₂

mass= moles x molar mass

from periodic table the molar mass of o₂ = 16 x2= 32 g/mol

mass=0.6422 moles x 32 g/mol = 20.6 grams of o₂